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OpenStudy (anonymous):
SOMEONE HELP ME D:!!! What value of x does f(x)=x^2-lnx have an absolute minimum?
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OpenStudy (anonymous):
the derivaitve of x^2-lnx is 2x-(1/x), Now this to zero and find the critical points
OpenStudy (anonymous):
okay i understand that but who do i find the critical points?
OpenStudy (anonymous):
how*
OpenStudy (anonymous):
equate its derivative to 0 and find the value of x
OpenStudy (anonymous):
x=1/sqrt(2)
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OpenStudy (anonymous):
The derivaitve :|dw:1323934982225:dw|
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