Question

2. What is the equation of the graph below?

(3 points)
y = –4(x + 2)2 + 2
y = –4(x – 2)2 + 2
y = 4(x – 2)2 – 2
y = 4(x + 2)2 + 2

Answer 1

your parabola opens down, so the leading coefficient must be negative. it also has vertex (-2,2) so it must look like
\[y=a(x+2)^2+2\]