Question

Solve by completing the square and then use the square root method to solve. Write your answer in set brackets with no spaces, such as {-1,2}.

x^2 - 4x - 32 = 0

Answer 1

\[x^2-4x=32\]
\[(x-2)^2=32+2^2=32+4=36\]
\[x-2=\pm\sqrt{36}\]
\[x-2=\pm6\]
\[x-2=6\iff x=8\]
\[x-2=-6\iff x=-4\]

Answer 2

How would i put that in brackets ?