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Mathematics 22 Online
OpenStudy (anonymous):

SOLVE: b^2-10b+24=0

OpenStudy (anonymous):

I got 4,6

OpenStudy (anonymous):

b^2-10b+24=0 (b - 6)(b - 4) = 0 b - 6 = 0 +6 +6 b = 6 b - 4 = 0 +4 +4 b = 4 So the answers are b =4 and b =6

OpenStudy (anonymous):

mitosuki - YAY!!! Thanks

OpenStudy (anonymous):

No prob :)

OpenStudy (anonymous):

LagrangeSon678 the third term has to be positive, it must be multiplied by 2 negatives then.

OpenStudy (anonymous):

yeah man, i just saw that, thanks

OpenStudy (anonymous):

No prob

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