Question

solve 0.3x^2=1.8x+0.3

Answer 1

help.

Answer 2

start with
\[.3x^2-1.8x -.3=0\]

Answer 3

then multiply by ten to get
\[3x^2-18x-3=0\] then perhaps the quadratic formula, or else factor if you can

Answer 4

ok.

Answer 5

kind of lost.

Answer 6

did you forget the quadratic formula?

Answer 7

no

Answer 8

did you get the answer?

Answer 9

i kind of got 2 square root of 5 +/-

Answer 10

I'll check your work, one sec...

Answer 11

no, that is wrong...

Answer 12

the formula is\[x={-b \pm \sqrt{b^2-4ac}\over2a}\]for equations of the form \[ax^2+bx+c=0\]
for you
a=3
b=-18
c=-3
use that info and tell me what you get

Answer 13

agree..but not exactly what am looking for the answer..

Answer 14

o-0
are you saying you agree with the quadratic formula?
I should hope so...

Answer 15

my work is asking for the solution set??

Answer 16

right, you will have two answers that make up that set as a result of the plus-or-minus part of the formula.
so just plug in the numbers and simplify, what do you get?