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Mathematics 20 Online
OpenStudy (anonymous):

Solve: log64^1/2 Answer: -1/6... How?

OpenStudy (anonymous):

can you be a little more explicit, do you mean (log 64)^1/2? or something else? and, the natural log or log of some base?

jhonyy9 (jhonyy9):

log base 2 from 64 inside squareroot

OpenStudy (anonymous):

Yes, (log64)^1/2 64 is the base.

OpenStudy (anonymous):

log base 64 of 1/2? what's the ^?

jhonyy9 (jhonyy9):

no 64 not canb being the base

OpenStudy (anonymous):

Sorry, it's hard to translate this onto here... It's log base 64 to the 1/2

OpenStudy (anonymous):

log base 64 of what, to the 1/2? you're missing a number?

jhonyy9 (jhonyy9):

how do you like makeing squareroot from the base of logarithm ?

OpenStudy (anonymous):

Never tried it jhonyy9 and |dw:1323988357254:dw|

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