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OpenStudy (vanz):
how do you solve this x2-4x+5 = 0
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OpenStudy (anonymous):
quadratic formula
OpenStudy (anonymous):
or AC method
OpenStudy (vanz):
whats the answer. I want to check :)
OpenStudy (anonymous):
-1 and 5
OpenStudy (anonymous):
i can write out the step if you want me to
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OpenStudy (anonymous):
It's not -1 and 5
OpenStudy (anonymous):
what is it?
OpenStudy (anonymous):
-1 * 5 = -5
OpenStudy (anonymous):
2 - i and 2 + i
OpenStudy (anonymous):
when you simplify it you get (x-5)(x+1)=0 right?
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OpenStudy (vanz):
noo because youre completing the square
OpenStudy (anonymous):
no that's wrong sorry
OpenStudy (anonymous):
i dont know what you want from me O.O lol sorry i couldnt help
OpenStudy (vanz):
lol its okay I got the answer now :) thanks for trying.
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