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Algebra
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what is square root of 2 over square root of 3
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\[\sqrt{\left(\begin{matrix}2 \\3 ?\end{matrix}\right)}\]
sqrt(2/3)
\[\frac{\sqrt2}{\sqrt3}=\frac{\sqrt2\cdot\sqrt3}{\sqrt3\cdot\sqrt3}=\frac{\sqrt6}{3}\]
\[\sqrt{2/3}\]
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