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Beth, a construction worker, attempts to pull a stake out of the ground by pulling on a rope that is attached to the stake. The rope makes an angle of 69.6 with the horizontal. If Beth exerts a force of 132.3 N on the rope, what is the magnitude of the upward component of the force acting on the stake? Answer in units of N
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\[132.3\sin 69.6=Fty\]124.002 N you need to do \[\sin 69.6=Fty/132.3N\] then \[132.3\sin 69.6 = Fty\]
draw a force diagram
Fty = 124.002N
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