Question

how do you solve 2500=100(1+.2x+.02x^2)

Answer 1

first step, multiply both sides by 1/100

Answer 2

second step, add both sides by -25

Answer 3

third step, the solution will be \(\frac{-b\pm \sqrt{b^2-4ac}}{2a}\)

Answer 4

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Answer 5

thank you, is there another way to solve this by factoring?
if so could someone explain it?

Answer 6

medals for all of you