Question

36^(3c)=sqrt6^(8c+6)

Answer 1

\[\Large 36^{3c} = \sqrt{6^{8c+6}}\]



\[\Large 36^{3c} = \left(6^{8c+6}\right)^{\frac{1}{2}}\]



\[\Large (6^2)^{3c} = \left(6^{8c+6}\right)^{\frac{1}{2}}\]



\[\Large 6^{2*3c} = 6^{\frac{1}{2}(8c+6)}\]



\[\Large 6^{6c} = 6^{\frac{1}{2}(8c)+\frac{1}{2}(6)}\]



\[\Large 6^{6c} = 6^{4c+3}\]



\[\Large 6c = 4c+3\]



\[\Large 6c-4c = 3\]



\[\Large 2c = 3\]



\[\Large c = \frac{3}{2}\]