Question

See attachment.

Answer 1

a rectangle has a max area for a given perimeter when the length and width are teh same
so
2(X+y) = 116
x +y = 58
maximize x*y
x = 29 and y = 29 give x * y 841
try x = 30 and y = 28 gives x * y = 840
so max area = 841 and length and width are the same at 29