Question

Find the values of m which one root of the equation 4x^2=mx-5 is three times the other root.

Answer 1

in a quadratic equation \[ax^2+bx+c=0\]
sum of roots=-b/a
product of roots=c/a
here a=4
b=-m
c=5
let the roots be L and N
L=3N
so now tha roots are N and 3N

sum of roots=>>
N+3N=m/4
4N=m/4
N=m/16

Product of roots =>>
N*3N=5/4
3N^2=5/4

Substitute the first equation in the second
3(m/16)^2=5/4
and solve for m

Answer 2

Thank you

Answer 3

=)

Answer 4

Impressive lalaly. You're the smartest girl on here besides myininaya

Answer 5

i know im not, But thanks hero :$

Answer 6

don't doubt yourself

Answer 7

Thats sweet, Merci :$