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evaluate 2x^-1y^3 if x=2 and y=-1
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insert 2 instead of x and insert -1 instead of y
\[2(2)^{-1}-1^{3}\]
like that now what do i do
\[2(2)^{-1}(-1)^{3}\]
\[n^{-1}=\frac{1}{n}\] \[n^3=n\cdot n\cdot n\]
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okay i understand that part i just need help with the combined part
so just multiply and subtract answers you get
(\[1/4* 1^{-3}\]
im confused
\[x^{-1}= 1/x\] so |dw:1324153439822:dw|
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wait \[1/4(1^{3})\]
plugging your numbers
|dw:1324153490541:dw|
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