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Mathematics 22 Online
OpenStudy (anonymous):

Arc Length: Set up the integral for the length of the curve. x=y^1/3, 0 < y< 2

OpenStudy (anonymous):

\[x=y^{1/3}, 0 \le y \le 2\]

OpenStudy (anonymous):

ask moneybird?

OpenStudy (anonymous):

disregard the other post above the last one I made, I don't know why it keeps duplicating previous posts.

OpenStudy (lalaly):

\[Arclength=\int\limits_{0}^{2}\sqrt {1+(\frac{dx}{dy})^2}\]

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