What do you need to add to 3m^3 +7m +12 to get the sum of 2m^2 + 3m- 7 ?
Yes, exactly.
2m^2 + 3m- 7 - (3m^3 +7m +12)
Could you please show me the process
I can do this just give me some time
distribute the minus sign, then collect like terms. what do you get?
It's long an d confusing
Yes first distribute minus then
collect like terms
then add like terms
3m^3 +7m +12 to get the sum of 2m^2 + 3m- 7 Arrange, 3m^3 + 2m^2 + 3m + 7m + 12 - 7 Now add terms with same variables and their expoents. 3m^3 + 2m^2 + 10m + 5
Cool Saif you are a legend
Thanks Anikate! =)
yw
np
Yes but when we add 3m^3 and 3m^3, it becomes 6m^3, but there is not m^3 in the answer
u didnt wrote any 3m^3 in the second thing.
No, the question goes like this: 3m^3 +7m +12 + (BLANK) = 2m^2 + 3m- 7 ?
-3m^3 + 2m^2 - 4m -19
What money bird said..
Actually u have to solve it this way, like u have: 2 + x = 5 And u have to find that "x" So for that u have to solve for x. x = 5 - 2 x =3
And moneybird how did you get that?
2m^2 + 3m- 7 - (3m^3 +7m +12)
Now, Apply the same example here, 3m^3 +7m +12 + (BLANK) = 2m^2 + 3m- 7 U have to solve for the "blank" "Blank" = (2m^2 + 3m - 7) - (3m^3 + 7m + 12)
unfathomable^
so the supposed answer minus the first question
@Mini stop spamming and get a life.
im boredddddddddddd
Yes! this is b/c as u are going to shift the expression on the other side, it will change it's signs.
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