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Complete the square. Solve for x: (x - 9)2 = 1.
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is that :\[\left( x-9 \right)^{2}=1\]
x-9 is either equal to -1 or 1. write two equations, and solve both.
Yes Pax
cathy is right... reversing the squares on both sides you would get: \[x-9=\pm1\]\[x=\pm1+9\] So, \[x= 1+ 9 = 10\] or \[x= -1+ 9 = 8\] x= 8,10
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