Question

Can someone please help me? Judy drove 20 miles from her house to a theater at an average rate of 50 miles per hour. Greg drove from his house to the theater in 1/3 of the time it took Judy to drive to the theater, and they arrived at the same time. If Judy left the house at 7:30 pm, when did Greg leave the house? The correct answer is 7:46pm but I can't figure it out why.

Answer 1

speed = distance /time
time for judy= 20/50 =>2/5 hours
convert into minutes.
time for judy =24mins, hence judy reach by 7:54pm
greg time (1/3)x24==8mins
they both reach same time so
7:54 -0:08
time will be 7:46pm

Answer 2

thanks much! :)

Answer 3

welcome

Answer 4

thnk u

Answer 5

Could someone provide a better/clearer answer?