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The legs of a right triangles measure (m − 3) in. and (n + 3) in. Which is the length of square of its hypotenuse?
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m2 + n2 − 6(m − n) + 18 m2 + n2 + 6(m − n) + 18 m2 + n2 + 6(m − n) + 9 m2 + n2 − 6(m − n) ?
1st. choice
Alright, thank you!
Using the Pythagorean Theorem: \[ \mbox{the square of the hypotenuse}= (m-3)^2+ (n+3)^2\] \[= m^2 -3m-3m+9+n^2+3n+3n+9 \] \[=m^2+n^2-6m+6n+18 \] \[=m^2+n^2-6(m-n)+18\]
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