The perimeter of the regular hexagon with its center at H is 48 and its apothem is 6* sq rt of 3. Which is the area of the shaded region?
5*(8*6sqrt3/2)=5*24sqrt3 =120sqrt3
A regular hexagon is made up of 6 equilaterial triangles. Each triangle has lengths of 48/6, or 8. The area of each triangle are A=(4)*(4sqrt(3)) So the area of the shaded region is five of these, or 80sqrt3
Thanks
Brett this is sure right ?
Oh i meant to give a medal to jhonyy9 not brett. 80sqrt3 isn't even a choice
120sqrt3 is right.
but i hope that you understand it sure why is 120sqrt3
I do understand, I saw what you wrote in your answer (the steps you wrote) and I understand a little bit better now.
ok good luck bye
I'm sorry, i thought that the traingles were length 8 on each side, so each would be A=8/2*4sqrt3 whichis is 16sqrt3 times 5 which is 80. what is wrong here?
I don't know enough to tell you what EXACTLY is incorrect, but I do know that it is wrong because it was not one of the given possible answers. It's alright though. :]
so the area of one triangle will be 8*6sqrt3/2 and after you need multiply this by 5
Brett ok ?
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