Question

What are the extremes of y=x square root of (8-x^2)

Answer 1

extremes means max n min values?

Answer 2

\[y=\sqrt{8-x^2}\] is the upper half of a semicircle with center at the origin and radius
\[\sqrt{8}=2\sqrt{2}\]

Answer 3

the max is therefore
\[y=2\sqrt{2}\] if
\[x=0\] and the minimum value is
\[y=0\] if
\[x=\pm2\sqrt{2}\]