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In a national chess tournament, 40% of the players are eliminated each day. If the tournament starts with 2,000 players, to the nearest integer, how many players will be present at the start of the 5th day of play? 1,229 819 480 259
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2000 * .6^4
How do you know that is what you are suppose to do? Like I mean where did the .6 come from and the 4 come from?
every day 40% (0.4) is eliminated which means .6 (60%) remain. So at the end of the first day, 2000 * 0.6 remain. At the end of the second day, 2000*0.6*0.6 remain. Third day, 2000*0.6*0.6*0.6 remain. In general, at the end of the nth day, 2000 * (0.6)^n remain.
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