Question

if h(x)=2g(x) - (1)/(g(x)) =2 and g'(0)=-1, find the exact value of h'(0). please please please help and show all steps!

Answer 1

Suppose h(x) = 1/g(x). What is h'(x) equal to?

Answer 2

By the chain rule,
h' = dh/dg . dg/dx
= -1/g^2 . g'
i.e.,
h'(x) = -g'(x)/g(x)^2

Therefore h'(0) = -g'(0)/g(0)^2


Now apply this procedure to your function h(x)