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Mathematics 20 Online
OpenStudy (anonymous):

49^x= √7^(2x+6)

OpenStudy (anonymous):

49^x = 7^(1/2 (2 x+6))

OpenStudy (anonymous):

yes thats the equation

OpenStudy (anonymous):

No that is your answer.

OpenStudy (anonymous):

i need a soultion my only options are x=1,x=-1x=3x=-3

OpenStudy (anonymous):

I would say x = 1

OpenStudy (anonymous):

what on earth?

OpenStudy (anonymous):

\[49^x=\sqrt{7}^{2x+6}\] \[7^{2x}=7^{\frac{1}{2}(2x+6)}\] \[2x=x+3\] etc

OpenStudy (anonymous):

etc means \[x=3\]

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