Question

u^2+2u-4=0
use the quadratic formula to solve.

Answer 1

\[u=-(\sqrt{5}+1) u=(\sqrt{5}-1)\]

Answer 2

\[u^{2}+2u-4=0\]
\[u=-2 +/- \sqrt{2^{2}-4\left( 1 \right)\left( -4 \right)}/(2)\]
\[=-2 +/-\sqrt{20}/(2)\]
\[=-2+/-\sqrt{4 \times 5}/(2)\]
\[=-2+/-2\sqrt{5}/(2)\] factor out a 2 from the top
\[=2(-1+/-\sqrt{5})/(2)\] divide the top and bottom by 2
\[u=-1+/- \sqrt{5}\]

Answer 3

from step 3 or anywhere else after that you can use a calculator to give you the answer in decimal form