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solve -2(3-m)+15=6m-4(m-20)
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-2(3-m) = -6 + 2m
-4(m-20) = -4m + 80
use both and substitute: -6+2m +15 = 6m-4m+80
hmm.. Now we end up with 2m on both sides.... this equation is erroneous
yea that is where i got confused
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indeed
ok thanks i thought so just needed a little reassurance
yw
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