Question

Can someone help me to solve the already intergrated problem so I can compare my answer absolute (6t - 3t^2) from x = 1 to x=0 + absolute (6t -3t^2) from x= 5 to x= 1

Answer 1

don't you mean from x=0 to x=2 and negative integral from x=2 to x=5 ... because the formula crosses x-axis at x=2.

Answer 2

we got 6t-3t^3... integrating reveals:

3t^2-t^3.

from x=0-2
4
from x= 2-5
-54

total area between graph and x-axis : 58