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Calculus1 22 Online
OpenStudy (anonymous):

evaluate as x approaches 0 (1-2cosx+cos^2(x))/x

OpenStudy (anonymous):

0, use taylor's expansion series or L'hospital's principle

OpenStudy (anonymous):

f(x) = 1-2cosx+cos^2(x))/x differentiate top and bottom: 2sinx + 2cosxsinx = 2sinx(1 + cosx) as x ---> 0 this approaches 0

OpenStudy (anonymous):

yeah use L'hospital's rule, lim=f '(x)/g '(x)

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