Question

x+2y+z=10
2x-y+3z=-5
2x-3y-5z=27
Please solve step by step please, Thanks!

Answer 1

What methods have you been working on, elimination, Cramers, row reduction or inverse?

Answer 2

elimination

Answer 3

sorry was away

Answer 4

x+2y+z=10 ...(1)
2x-y+3z=-5 ...(2)
2x-3y-5z=27...(3)
2(1)-2:
5y-z = 25 ...(4)
(2)-(3):
2y+8z=-32 ...(5)
2(4)-5(5):
-42z=210
=> z=-5 ...(6)
substitute (6) into (4)
5y-(-5)=25
y=(25-5)/5=4 ....(7)
Substitute (6) and (7) into (1)
x+2(4)+(-5)=10
=> x=7

So (x,y,z)=(7,4,-5)

Answer 5

Thanks!!

Answer 6

Omg i can't thank you enough

Answer 7

You're welcome!