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4[x-(3-2x)]+5=3(x+11)
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\[4[x-(3-2x)]+5=3(x+11)\]\[4x-4(3-2x)+5=3x+33\]\[4x-12-(-8x)+5=3x+33\] \[4x+8x-12+5=3x+33\]Now subtract 3x from both sides and add 7 to both sides \[12x-3x-7+7=3x-3x+33+7\]\[9x=40\] \[x=40/9\]
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