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HELP PLEASE Find the value of x
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16.97 i think
\[\cos 45=\frac{12}{x}\]
\[x=\frac{12}{\cos45}\]
wait im confused LaLaly
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its a right triangle, so u use, Cos angle = adjacent/hypotenuse
so divide 12 by 45?
no. first find cos45, which is 1/root2 then divide 12 by that. the answer should be 16.97
still confused :? but thank you
what is cos 45?
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do you know basic trignometry?
trignometry? ha i dotn think so this is suppose to be geometry
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