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URRGGEENNTT!!! :) Solve the following system using the substitution method. 16x + 3y = 0 8x + y = 1
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16x + 3y = 0 8x + y = 1
y=-8x+1
plug that in first equation wherever you see y
thank you so much!
(-3/8, 2)....(3/8, -2)....(-3/8, -2)....(3/8, 2) those are the answers. i cant figure out which one it is.
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16x + 3y = 0 plug that in first equation wherever you see y y=-8x+1 16x+3(-8x+1)=0 solve for x x=3/8
y=-8(3/8)+1 y=-3+1=-2
(3/8,-2)
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