If you were to use the elimination method to solve the following system, choose the new system of equations that would result after the variable z is eliminated in the first and second equations, then the second and third equations.

x + y – 3z = –8
2x + 2y + z = 12
3x + y – z = –2

Question

If you were to use the elimination method to solve the following system, choose the new system of equations that would result after the variable z is eliminated in the first and second equations, then the second and third equations.

x + y – 3z = –8
2x + 2y + z = 12
3x + y – z = –2

anonymous · Answer

multiply second by 3 and add  to give
7x+7x =  28
add second and third
5x + 3y = 10

anonymous · Answer

These are the answer choices. so it would be the second choice right?
7x + 7y = 28
3x + y = –2 
   
7x + 7y = 28
5x + 3y = 10 

 x + y = –8
3x + y = –2 

 x + y = –8
5x + 3y = 14