Question

Find the 9th term of the geometric sequence with a2 = 0.3 and a6 = 0.00003.

Answer 1

ar = 0.3

ar^5 = 0.00003

Answer 2

r = 1/10

a = 3

t9 =ar^8 = (3) (0.1)^8 = 0.00000003

Answer 3

ar^5 / ar = r^4 = 0,00003/0.3 = 0.0001
r = 0.1
a=3
9th term = ar^8 = 3 * 0.1^8 = 0.00000003