Question

how do you solve x^2-12x+4=0 ?

Answer 1

Quadratic formula!

Answer 2

use the quadratic formula since it will not factor.

Answer 3

or completing the square

Answer 4

x^2-12 x+4 = 0
Subtract 4 from both sides:
x^2-12 x = -4
Add 36 to both sides:
x^2-12 x+36 = 32
Factor the left hand side:
(x-6)^2 = 32
Take the square root of both sides:
sqrt(x-6) = 4 sqrt(2)
Eliminate the absolute value:
x-6 = -4 sqrt(2) or x-6 = 4 sqrt(2)
Add 6 to both sides:
x = 6-4 sqrt(2) or x-6 = 4 sqrt(2)
Add 6 to both sides:
x = 6-4 sqrt(2) or x = 6+4 sqrt(2)

Answer 5

^what she did :)