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using double-angle or half-angle identities, find the exact value of: sin 5(Pie)/12
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75 degrees?
No that's not it
are u sure its limited only for half and double angles?
yup
\[\sin \left( 5 \pi \over 12 \right) = \sin \left({1 \over 2} \times{5 \pi \over 6} \right)\]
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yup
i got it
what did you get?
\[\sin \left(5 \pi \over 12 \right) = \[\sqrt{1-\cos \left( 5\pi \over 6 \right)\over2}=\sqrt{1+{\sqrt{3}\over2}\over2}= {{\sqrt{2+\sqrt{3}}\over 2} }=\]
\[={\sqrt{2}+\sqrt{6}\over4}\]
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