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Please help me again with this... (x+y)^2 ------- + y z if x = -1 y = 2 z = -2 z
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HAT?
hello shinigami1m...it's an evaluation of algebra
\[\frac{(x+y)^{2}}{z} + y = \frac{3}{2}\] if x = -1 y = 2 z = -2
JohnnyRocket your answer is 3/2?
\[\frac{-1+2}{-2}+2\]\[-\frac{1}{2}+2\]\[\frac{-1+4}{2}\]\[x=\frac{3}{2}\]
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Nancy Lam should I make it a mixed number because it is improper or 3/2 is okay when it comes to algebra?
its just fine dear
unless ur teacher told u to do so
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