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OpenStudy (anonymous):
solve 2log(x+11)=(1/2)^x.
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OpenStudy (anonymous):
what's log's base?
OpenStudy (anonymous):
10
OpenStudy (anonymous):
Oh okay...
OpenStudy (anonymous):
\[2\log (x+ 11) = \left( \frac{1}{2}\right)^x\]
OpenStudy (anonymous):
that is the question right?
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OpenStudy (anonymous):
Yeah, let me show you what I've got so far.
OpenStudy (anonymous):
|dw:1324553869100:dw|
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