Question

Answer check:
(y+3)(y-3) < 0
y^2 - 9 < 0
y^2 < 9
y < 3
correct?

Answer 1

yeah

Answer 2

its right

Answer 3

i need to break it up into
(y+3) < 0 &
(y-3) <0 ?

Answer 4

not complete

Answer 5

y^2 < 9

-3< y<3

Answer 6

oh i forgot about the plus or minus, when square rooting. thank you.

Answer 7

because -4 wouldn't work
(-4+3)(-4-3)=-1*-7=7
which is bigger than 0

Answer 8

-3<y<3