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y '= 1 + 3x - 2y, y (1) = 2 Determine an approximation to y (2) by use of Euler's method with step-by-step length 0.25.
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\[y_{n+1}=y_n+ y'_n(h)\]
h=1 x=1.25 y(1.25)=y(1)+y'(x,y)(.25) =2 + 2(.25)
do it three more time
\[y=(1/4)+(3x/2)+K*1/(e^2x+C)\] Equation itself, the K and C being constants of integration
This is numerical solution problem
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