Question

Which of the following represent the zeros of f(x) = 6x3 – 31x2 + 4x + 5 ?

Answer 1

(x-5)(2x-1)(3x+1)=0

Answer 2

f(5)=0 , so f(x)=(x-5)(6x^2-x-1),
and the roots of (6x^2-x-1)=0 are x1=0.5 and x2=-1/3
Then f(x)=(x-5)(6x^2-x-1)=(x-5)6(x-0.5)(x+1/3)
f(x)=(x-5)(2x-1)(3x+1)