Question

Find parametric equation for rectangular equation:
(y+3)^2 = 4(x-2)

Answer 1

(y+3)^2+8
----------- =x
4

(y+3)=t

y= t-3

x= t^2+8
--------
4

Answer 2

should be sideway parabola

Answer 3

you will see that they are same

http://www.wolframalpha.com/input/?i=Plot%5B%28y%2B3%29%5E2+%3D+4%28x-2%29%2C%7Bx%2C0%2C6%7D%2C%7By%2C-6%2C1%7D%5D

ParamtricPlot{(t^2+8)/4,t-3}

Answer 4

thank you

Answer 5

I don't get this part
x= t^2+8
--------
4

Answer 6

I set t to be t=y+3

and plug into here

(y+3)^2+8
----------- =x
4

Answer 7

ok,
i got it