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find the simplified form of (12f^6g)/(16g^2)
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3f^6/4g
i dont think will be like that bcos g is in power of f
no it is not. it is f to the 6th power times g :)
I will leave it to Diya.
\[\frac{3f^6}{4g}\] is right!
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i know lol thank u :)
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