Question

What is the 32nd term of the arithmetic sequence where a1 = 12 and a13 = –60?

Answer 1

tn= a+(n-1)d
-60= 12+(13-1)d
-60=12+12d
-72=12d
d=-6

tn=a+(n-1)
= 12+ (32-1)-6
=12+ (31x-6)
= 12-186
=-174

Answer 2

thanks so much!

Answer 3

no problem