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Find the product (8x^2-5y)(8x^2+5y)
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i think the answer would be 64x^4 - 25y^2
yeah it is I have it broke down right here 64x^2-25y^2 = (8x)^2-(5y)^2 = (8x-5y)(8x+5y)
approximate the area of the region R which is bounded above b the parbola y=x^2+1, below by the x-axis, on the left by the line x=-2 and on the right by the line x=3. can u find the answer?
i think the best solution would be to integrate the function y, and then compute: Y(x=3)-Y(x=-2)
64x^4-25y^2
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