Question

Use the quadratic formula to find the roots of the equation. Round to tenths place if necessary.
11x2 - x - 3 = 0
A. {-1, 1.2}
B. {-11, 13.2}
C. {-0.5, 0.6}
D. no real solution

Answer 1

c

Answer 2

\[\Large \begin{array}{l}
\frac{{1 \pm \sqrt {1 - 4(11 \cdot - 3)} }}{{2 \cdot 11}}\\
= \frac{{1 \pm \sqrt {133} }}{{22}}\\
= 0.57, - 0.48\\
= 0.6, - 0.5
\end{array}\]