3x^2-2√(3)xy+y^2+2x+2√(3)y=0
determine the type of conic, solve for y, determine the angle of rotation-use the formula cot2=A-C/B
and rewrite the equation of the conic using the equation x=x'cos-y'sin and y=x'sin+y'cos

i can't find that! =/

Question

3x^2-2√(3)xy+y^2+2x+2√(3)y=0
 determine the type of conic, solve for y, determine the angle of rotation-use the formula cot2=A-C/B
 and rewrite the equation of the conic using the equation x=x'cos-y'sin and y=x'sin+y'cos

i can't find that! =/

anonymous · Answer

WOW! You have hard problems... (I am SUCH a big help)

anonymous · Answer

I don't know how to do this... :,(

anonymous · Answer

lol, yea it's very complicated =/

anonymous · Answer

hate math with a passion!

anonymous · Answer

This seems really advanced. What class is this for?

anonymous · Answer

it seems as this is a quadratic equation in the form:Ax^2 + Bxy + Cy^ 2 + Dx + Ey + F = 0
now the reason you are asked for the rotation, is because of the Bxy term. Now lets see if we can apply the discriminate B^2-4AC, to determine the type of conic

anonymous · Answer

So, we have B=-2sqrt(3) and A=3 and C=1, so let do that computation: 
(-2sqrt(3))^2-4(3)(1)

4(3)-12=12-12=0, thus we have a parabola

anonymous · Answer

=o=

anonymous · Answer

Now we have to actually find the angle of rotation, we have at our disposal two equations, although we are told explicitly to use|dw:1324962327278:dw|