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FIND THE THIRD,FIFTH AND TENTH TERM SEQUENCE DESCRIBED BY EACH RULE A(n)=4+(N-1)(-5) A(N)=-2(n-1)(-5)
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for the first one: A(3)= 4 + (2)(-5) = -6 A(5)= 4 + 4(-5) = -16 A(10)= -41
why dont you try the second and tell me what you get lets see if you've got the way
A(3)=-2(4)(-5)=40
AM I RIGHT?
n-1 = 3-1 = 4??!!!!
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HUH?
OH CRAP I GOT IT ...
A(3)=-2(2)(-5)=20
yup now it is correct :D
ARE U A TESCHER HOBLOS?
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!!!nope
YOU TEACHER WAY!!!!!!!!!!!!!!!!!!!!!!!!!1 BETTER THAN MY TEACHER
hahahaha thanks :D
A(5)=-2(4)(-5)=40
yup.... one more
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A(10)=-2(9)(-5)=90
good job :D
:p
I HAVE A FEW MORE BUT DIFFERENT STYLE HAHA
post them and i'll see if i can help ;)
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