Question

how to solve this quadratic equation 10z2+19z+6=0

Answer 1

you need to find factors of 10 and 6 which when added give 19
5 * 3 and 2 * 2 will fit the bill:

so ( 5x + 2)(2x + 3) = 0
5x + 2 = 0 or 2x + 3 = 0
x = -2/5 or x = -3/2

solution set is -2/5 , -3/2

Answer 2

thanks for replying sir.

Answer 3

yw