Question

Find the equation in standard form which passes through (3, –6) and (–2, –1). You must show all work.

Answer 1

The formula for finding the equation of line when two points are given is
(y-y1)=(x-x1)(y2-y1)/(x2-x1)
Now
y+6=(x-3)(-1+6)/(-2-3)
y+6=(x-3)(-1)
y+6=-x+3
x+y+3=0

Answer 2

Nice job Atchyut!